CEED Cutoff 2020

CEED Cutoff 2020 - IIT Bombay will release CEED 2020 cutoff for candidates who wish to seek admission to postgraduate design programmes at IISC Bangalore and various institutes of IIT. To be eligible for admission, CEED aspirants need to obtain equal to or above CEED cutoff 2020. The participating institutes such as IIT Kanpur, IIITDM Jabalpur, IIT Guwahati, IIT Bombay, IIT Hyderabad, IIT Delhi and IISc Bangalore will release category-wise CEED cutoff for respective programmes. Students should be aware of the fact that the CEED cut off will not be the same across institutes and it will vary from programme to programme. CEED 2020 was held on January 18 in two parts- Part A and Part B. Only the shortlisted candidates in part A were eligible to appear for part B. The score of part B will be used for preparation of CEED 2020 cutoff and merit list. Go through this article to know about CEED off 2020 in detail.
Latest: The final answer key of CEED 2020 released on February 4. CEED 2020 result will be declared on March 4.

CEED Cutoff 2020 Important Dates

What are the factors that determine CEED Cutoff

The cutoff of CEED 2020 will be influenced by many factors, such as

• Previous years’ cutoff trends

• Difficulty level of the question paper

• Performance of candidates in CEED 2020

• Total number of candidates appearing for CEED 2020

• Total number of sanctioned seats in each programme

CEED Cutoff 2020- Important Highlights

• CEED 2020 question paper have two parts- Part A and Part B.

• Part A is a screening test for shortlisting candidates for Part B.

• The merit list of CEED 2020 will be prepared on the basis of Part B score, which will include both the opening and closing ranks of qualified candidates for counselling round. Candidates must note that the closing rank is also CEED 2020 cutoff.

• The cutoff of each participating institute of CEED 2020 will vary

CEED Cutoff 2020 - Paper A

Paper A was of one hour and 100 marks were allotted for the same. The questions were of of multiple type questions (MCQs) and Numerical Answer Type (NAT). The candidates had to score the minimum percentage specified for their respective category in order to qualify in this part. The cutoff for various categories will be calculated in the following manner given in the table:

Candidates must score equal to or more than the given below minimum marks in Part A to be shortlisted for part B.

Category-wise minimum per cent of marks needed to qualify CEED 2019 part A

CEED 2020 Cutoff Part B

Part B consisted of eight questions of 100 marks. Questions 1 to 5 is allotted 40 marks each, candidates were given an option to attempt any one of these questions. A normalised score ‘S’ was calculated by using the following formula:

S = {(m − μi) Σ / σi} + A, wherein

• m= is the raw marks obtained in question i

• μi = the average of the raw marks obtained by all candidates who opted for question i

• σi = the standard deviation of the raw marks secured by all candidates who answered question i

• A = 20 and Σ = 5 the average and the standard deviation, respectively, of the distribution of scores ‘S’. If the calculated ‘S’ score for any candidates is below 0, all such scores will be capped at 0, and if the calculated ‘S’ score for any candidate is above 40, all such scores will be capped at 40.

Marks obtained by candidate in other questions in part B will be added to ‘S’ for securing the part B score.

CEED Result 2020

IIT Bombay will announce the result of CEED 2020 in online mode on March 4. To download the result, candidates have to enter their registered email ID and password.

IIT Bombay conducts Common Entrance Exam for Design for offering admission to qualified candidates in Master of Design (M.Des.) programmes offered by the participating institutes. Each participating institute may also conduct further tests or interviews for the final selection. CEED 2020 score card will be valid for one year from the day of result declaration.