Pearl Academy M. Des 2025
No. 1 Design & Fashion Institute by ASSOCHAM, India Today, Outlook and The Week rankings
CEED qualifying cutoff 2024 is out. CEED 2024 qualifying cutoff for part A for general category is 50.26. IIT Bombay, has released the CEED 2024 part A cutoff. As per UCEED exam cutoff 2024, the mean and standard deviation for Part-A (CEED 2024) are 41.90 and 16.72, respectively. The CEED cut off 2024 is updated on its official site, ceed.iitb.ac.in. The CEED 2024 cut off has been released in the form of a mean and a standard deviation. The mean and standard deviation is calculated based on the performance of all the candidates who appeared for CEED Part A. CEED result download link is available at ceed.iitb.ac.in. Read the complete article to know more about CEED cut off 2024.
Category | CEED 2024 Cut off for Part A |
Open | 50.26 |
EWS | 45.23 |
OBS | 45.23 |
PwD | 25.13 |
SC | 25.13 |
ST | 25.13 |
Particular | CEED 2024 cut off |
---|---|
Mean Deviation | 41.90 |
Standard Deviation | 16.72 |
Aspiring students are required to obtain the specified minimum percentage of CEED total marks as per their category to qualify for Part A. As per the CEED cutoff for IIT Bombay category, the CEED Part A cut off 2024 is calculated in the following aspect mentioned in the table.
Particular | CEED 2024 Cut off marks for the Open category | CEED 2024 Cut off marks for the OBC-NCL category | CEED 2024 Cut off marks for ST, SC, and PWD category |
CEED Cutoff 2024 | µ + (σ 2) = δ where µ and σ are the average marks and standard deviation of the distribution of marks obtained by all the candidates in CEED Part-A. The µ and σ will be rounded off to two decimal places | The cutoff for OBC-NCL category candidates will be 0.9? | The cutoff SC, ST, and PWD categories will be 0.5δ |
Particular | CEED 2023 cutoff |
Mean Deviation | 22.59 |
Standard Deviation | 11.82 |
Category | CEED Part A Cut off Marks |
Open | 24.58 |
EWS | 22.12 |
OBC | 22.12 |
PwD | 12.29 |
SC | 12.29 |
ST | 12.29 |
The IIT Bombay CEED cutoff 2024 is determined by certain parameters. The CEED 2024 cut off mark for Part A is the minimum mark students need to secure to qualify for Part A. Note that CEED Part B cutoff 2024 will be evaluated only if the candidate has qualified for Part A.
Aspiring students are required to secure a minimum CEED rank for IIT Bombay and other IIT campuses to gain M.Des admission at Kanpur, Guwahati, Hyderabad, Delhi, Roorkee, IIITDM Jabalpur, and IISc Bangalore.
The CEED 2024 cut off is the minimum score that candidates need to qualify for the next stage of the admission process. The cutoff varies depending on the programme, category, and institute of the candidates. The CEED exam has two parts: Part A and Part B. Part A is a computer-based test that evaluates the candidates’ design aptitude and analytical skills. Part B is a pen-and-paper test that assesses the candidates’ drawing, creativity, and communication skills. Only the candidates who score above the CEED Part A cut off are shortlisted for Part B evaluation. The final CEED score is calculated based on the marks obtained in Part B only.
The final CEED score is calculated by giving 25% and 75% weight to marks obtained in Part-A and Part B respectively. Based on the past year's CEED cut-off, we mention the qualifying marks. Candidates can check the CEED cutoff for IIT for reference purposes.
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Categories | CEED Minimum Qualifying Marks | Minimum percentage required in Part A for shortlisting |
Open | 27.30 | 10% |
OBC-NCL/EWS | 24.57 | 9% |
SC/ST | 13.65 | 5% |
PwD | 13.65 | 5% |
Cutoff trends of previous years
The difficulty level of the exam
Performance of the candidates in the exam
Total number of candidates appearing in CEED 2024
No. of seat Intake
Check Also:
Candidates can check out the important highlights of the CEED 2024 cut off, which are mentioned below.
The question paper for CEED 2024 has two parts - Part A and Part B.
The first part of CEED i.e. Part A is a computer-based test that evaluates the candidates’ design aptitude and analytical skills. Only the candidates who score above the Part A cutoff are shortlisted for Part B evaluation.
Part B is a pen-and-paper test that assesses the candidates’ drawing, creativity, and communication skills. The final CEED score is calculated based on the marks obtained in Part B only.
Based on the score of Part B the concerned authority will prepare the CEED merit list 2024 which includes both the opening and closing ranks of the candidates who qualified for the CEED counselling stage.
The closing rank will be the cutoff of CEED 2024.
Each participating institute will have a different cutoff.
The correlation between CEED marks and rank is a critical factor in determining a candidate’s admission into a design program. Higher CEED marks usually translate to a lower rank, increasing the chances of securing a seat in a preferred institute. Therefore, the candidates have to obtain good marks and CEED rank for IIT Bombay admission and into other participating institutes.
CEED part B will be evaluated manually for the candidates who qualify for part A. CEED part B contains a subjective question and there are no model solutions for the same. The minimum percentage is mentioned in the table below.
Category | CEED Cutoff (Minimum percentage of marks in Part A to be shortlisted for Part B) |
Open/General | 10% |
OBC (NCL) | 9% |
SC/ ST/ PwD | 5% |
IIT Bombay may make changes in the CEED shortlisting criteria for 2024. The formula to calculate the CEED cutoff may change from the previous year. The expected formula to determine CEED shortlisting criteria is as follows: µ + (σ 2) = δ, where µ and σ are the average marks and standard deviation of the distribution of marks obtained by all the candidates in Part-A of CEED 2024.
The µ and σ will be rounded off after the first decimal place. The candidates belonging to the reserved categories shall have to fulfil a relaxed cut-off mark, which will be:
0.9? for OBC-NCL
0.9? for EWS
0.5? for SC/ST
0.5? for PwD
The shortlisting criteria for CEED 2024 are not yet announced by IIT Bombay, the conducting authority of CEED. The tentative formula and factors that determine the shortlisting criteria are based on the previous year’s trends and may change due to various reasons. Candidates should check the official website of CEED for the latest updates on the CEED 2024 shortlisting criteria.
Candidates can find below the CEED last year cutoff for 2022, 2021, and 2020. Last year, IIT Bombay has not officially released the cutoff of CEED 2022.
Particulars | Category | |||
Gen | OBC - NCL | SC/ST | PwD | |
Part A Qualifying Mark | 24.58 | 22.12 | 12.29 | 12.29 |
Qualifying CEED Score | 30 | 27 | 15 | 15 |
Particulars | Category | |||
Gen | OBC - NCL | SC/ST | PwD | |
Part A Qualifying Mark | 38 | 34.2 | 19 | 19 |
Qualifying CEED Score | 30 | 27 | 15 | 15 |
For reference, candidates can go through CEED 2020 qualifying marks in Part A of the exam as well as CEED score in the table below:
Category | CEED 2020 Part A Qualifying Marks | CEED Qualifying Score 2020 |
Open | 38 | 30 |
OBC-NCL | 34.2 | 27 |
SC | 19 | 15 |
ST | 19 | 15 |
PwD | 19 | 15 |
IIT Bombay declared the CEED result 2024 in online mode. Aspirants can check the result of CEED 2024 by entering the required credentials in the login window. Aspirants will be able to download the CEED 2024 scorecard from the official website of CEED. The CEED score for IIT Bombay will be available on this page. CEED scorecard 2024 is valid for one year from the date of the result declaration.
The CEED 2024 cut off marks was released by IIT Bombay after the declaration of the results.
You can check your CEED 2024 result and scorecard by entering your email id and password in the login window on the official website of CEED 2024. The result will display your marks obtained in Part A and Part B, and your qualifying status. The scorecard will contain your details, such as name, roll number, photograph, signature, category, and CEED score and rank.
The factors determined while preparing the CEED cutoff for IIT Bombay are as follows
Total number of candidates appearing in the CEED
Previous year cutoff trends
Number of seat availability
Students performance in the entrance test
The CEED 2024 scorecard is valid for one year from the date of its issue.
Application Date:04 October,2024 - 31 December,2024
Application Date:22 November,2024 - 06 January,2025
Actually You'll be eligible for both years CEED 2025 & CEED 2026.
You can give CEED 2025 because during that time you'll be in your last year of graduation and you're eligible to give CEED EXAM while you're in your final year of graduation.
BUT remember one thing that if you are applying in 2026 you will be eligible for year 2027 session which will be loss of your one precious year so be careful and decide what you want.
Hello,
Maybe, because When it comes to eligibility for the CEED (Common Entrance Examination for Design), having backlogs in your undergraduate program may not necessarily disqualify you from appearing for the exam. However, it is important to note that each institute has its own specific eligibility criteria for admission to their MDes programs. Some institutes may consider backlogs as a factor during the admission process, while others may not.
Hope this helps you,
Thank you
https://www.google.com/amp/s/design.careers360.com/exams/ceed/amp
Hello,
You can download sample papers for CEED Examination from the link given below -
https://design.careers360.com/articles/ceed-sample-papers
------ Also if you want previous year papers , sample papers, mock tests then I would like to inform you that you can find it on the web.
You just have to open your browser, type the name of the entrance examination and the year for which you seek PYQ paper and then after you search it, you will find numerous results for your query.
There are various sites available that provide all these information without charges, you can save it from there for future reference.
Thank you.
Hello,
Mdes is an excellent degree for creative people, and your job and compensation will improve as a result. You can, in fact, apply for MDES.
You must succeed in the CEED, an annual design entry test. The majority of Indian schools, including NITs and IITs, accept CEED scores as proof of eligibility for MDes.
A select few universities, like IIT Kanpur and IISC Bangalore , also accept GATE scores. Engineering students have a second opportunity to apply for MDes without having to submit a CEED score.
BE, BTech, BDes, or BArch with a minimum cumulative GPA of 50 percent (pass grades for SC/ST) are required.
GATE / CEED score (70 percent weighting) with an online design aptitude test and an interview make up the IISc Bangalore selection process (30 percent weightage).
Good Luck!!
Hello aspirant,
Hope you are doing well...!!!!
If you have any desire to take B des course in movement After twelfth class and after B des, M des configuration course in activity then you need to show up for entrance test like NIFT entrance, UCEED,CEED,NID entrance, NATA,. Plan in activity with a decent stamps and need to get ready for an intrigued like NID entrance with regards to NIFT entrance, CEED,UCEED. Can you ought to be graduate in planning course or designing course after that he needs to show up for assistants test for M plan in movement. The choice for confirmation is done on the legitimacy premise and stamps got in entrance tests.
Hope this information helps you!!!!
All the best!!!
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