CEED Cutoff 2020
Updated on Jan 18, 2020 - 2:18 p.m. IST by Khushboo Verma
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CEED Cutoff 2020 - IIT Bombay will release CEED 2020 cutoff for candidates who wish to seek admission to postgraduate design programmes at IISC Bangalore and various institutes of IIT. To be eligible for admission, CEED aspirants need to obtain equal to or above CEED cutoff 2020. The participating institutes such as IIT Kanpur, IIITDM Jabalpur, IIT Guwahati, IIT Bombay, IIT Hyderabad, IIT Delhi and IISc Bangalore will release category-wise CEED cutoff for respective programmes. Students should be aware of the fact that the CEED cut off will not be the same across institutes and it will vary from programme to programme. CEED 2020 was held on January 18 in two parts- Part A and Part B. Only the shortlisted candidates in part A were eligible to appear for part B. The score of part B will be used for preparation of CEED 2020 cutoff and merit list. Go through this article to know about CEED off 2020 in detail.
Latest: Check details about CEED Exam Analysis 2020. IIT Bombay will declare the draft Answer Key of CEED 2020 on January 21.

CEED Cutoff 2020 Important Dates

Events

Dates

CEED 2020

January 18, 2020

CEED 2020 result declaration

March 4, 2020

Download of CEED 2020 score card

March 4, 2020

What are the factors that determine CEED Cutoff

The cutoff of CEED 2020 will be influenced by many factors, such as

  • Previous years’ cutoff trends

  • Difficulty level of the question paper

  • Performance of candidates in CEED 2020

  • Total number of candidates appearing for CEED 2020

  • Total number of sanctioned seats in each programme

CEED Cutoff 2020- Important Highlights

  • CEED 2020 question paper have two parts- Part A and Part B.

  • Part A is a screening test for shortlisting candidates for Part B.

  • The merit list of CEED 2020 will be prepared on the basis of Part B score, which will include both the opening and closing ranks of qualified candidates for counselling round. Candidates must note that the closing rank is also CEED 2020 cutoff.

  • The cutoff of each participating institute of CEED 2020 will vary

CEED Cutoff 2020 - Paper A

Paper A was of one hour and 100 marks were allotted for the same. The questions were of of multiple type questions (MCQs) and Numerical Answer Type (NAT). The candidates had to score the minimum percentage specified for their respective category in order to qualify in this part. The cutoff for various categories will be calculated in the following manner given in the table:

Categories

Cutoff marks for Open category

Cutoff marks for OBC-NCL category-

Cutoff marks for ST, SC, PWD category

CEED cutoff 2020

X + ½ Σ, where X is the average marks scored by the candidate in Part A and Σ is the standard deviation


The cutoff for shortlisting candidates who fall under OBC-NCL category candidates will be 90% of the open category.



The cutoff for shortlisting candidates under SC, ST, PWD category will be 50% of the open category.


Candidates must score equal to or more than the given below minimum marks in Part A to be shortlisted for part B.

Category-wise minimum per cent of marks needed to qualify CEED 2019 part A

Category

CEED 2020 Cutoff (Minimum percentage of marks in Part A to be shortlisted)

Open/General

10%

OBC (NCL)

9%

SC/ ST/ PwD

5%

CEED 2020 Cutoff Part B

Part B consisted of eight questions of 100 marks. Questions 1 to 5 is allotted 40 marks each, candidates were given an option to attempt any one of these questions. A normalised score ‘S’ was calculated by using the following formula:

S = {(m − μi) Σ / σi} + A, wherein

  • m= is the raw marks obtained in question i

  • μi = the average of the raw marks obtained by all candidates who opted for question i

  • σi = the standard deviation of the raw marks secured by all candidates who answered question i

  • A = 20 and Σ = 5 the average and the standard deviation, respectively, of the distribution of scores ‘S’. If the calculated ‘S’ score for any candidates is below 0, all such scores will be capped at 0, and if the calculated ‘S’ score for any candidate is above 40, all such scores will be capped at 40.

Marks obtained by candidate in other questions in part B will be added to ‘S’ for securing the part B score.

CEED Result 2020

IIT Bombay will announce the result of CEED 2020 in online mode on March 4. To download the result, candidates have to enter their registered email ID and password.

IIT Bombay conducts Common Entrance Exam for Design for offering admission to qualified candidates in Master of Design (M.Des.) programmes offered by the participating institutes. Each participating institute may also conduct further tests or interviews for the final selection. CEED 2020 score card will be valid for one year from the day of result declaration.

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More like CEED

Questions related to CEED

Showing 145 out of 145 Questions
3 Views

hii M completed b.sc and diploma in interior designing(3 yrs) is it enough to eligible for CEED exam..?

Aditi Amrendra Student Expert 12th Jan, 2020
Hello,


CEED 2020 eligibility criteria requires :

A candidates must have passed a degree/diploma/postgraduate degree programme of 4 years or 3+2 years.
Candidates who will be taking the final exam of such programmes by July 2020 or those who have passed GD Arts diploma programme by July 2019 can also apply.


https://design.careers360.com/articles/ceed-eligibility-criteria


I hope this helps.
5 Views

hii M completed b.sc and diploma in interior designing(3 yrs) is it enough to eligible for CEED exam..?

Aditi Amrendra Student Expert 12th Jan, 2020
Hello,


CEED 2020 eligibility criteria requires :

A candidates must have passed a degree/diploma/postgraduate degree programme of 4 years or 3+2 years.
Candidates who will be taking the final exam of such programmes by July 2020 or those who have passed GD Arts diploma programme by July 2019 can also apply.


https://design.careers360.com/articles/ceed-eligibility-criteria


I hope this helps.
2 Views

hii M completed b.sc and diploma in interior designing(3 yrs) is it enough to eligible for CEED exam..?

ayush mishra 12th Jan, 2020

Hey Aniket!

CEED 2020 eligibility criteria in terms of educational qualifications is as follows:-

• A candidate with any recognized degree/diploma/post graduate degree program of 4 years or 3+2 years(after 10+2 level) or 3 years after 10+2 can apply.

• Candidates in their final year or who are awaiting their results can also apply for the same.

• Also GD Arts Diploma candidates who have passed the program by July 2020 can apply.

Hope it helps.

1 View

hii M completed b.sc and diploma in interior designing(3 yrs) is it enough to eligible for CEED exam..?

Akram Khan 12th Jan, 2020

Hi,

CEED - is COMMON ENTRANCE EXAM FOR DESIGN 2020. The eligibility to appear for CEED exam is

Candidates must have completed a degree / diploma / post graduate degree programme of minimum 3 years (after 10+2 level), or must be appearing for the final examination of such a program by July 2020, or must have passed the GD Arts diploma programme (10+5 level) by July 2020.

So you are eligibile to appear for CEED exam. However admission criteria for different college is different than eligibility for appearing ceet exam. so you should also check college admission eligibility criteria in which you want to take admission.

Hope you find this information helpful.


14 Views

is exam pattern for CEED and NIFT same?

Harshita Gupta 4th Dec, 2019
Hey,


The exam pattern of both the exams is little different.

CEED examination ( conducted by IIT , Bombay) consists of 2 sections- A and B. Section A will contain 41 questions and section be will contain 5 questions( 20 marks each question). Both section will be of 100 marks each. Part A will be computer based and B will be pen- paper based.

Part A will be a screening test and those who qualify part A will be evaluated for part B.

And for NIFT , the GAT paper for B.Des will consist of 100 questions and the total marks of examination is also 100. And for B.F.Tech, the number of questions will be 150. The exam is offline, paper based.

And CAT paper will consist of 3 questions and marks will be out of 100.
Admission in B.F.Tech will be fully based on GAT whereas for B.Des the weightage of CAT is 50% , GAT is 30% and situation test will be of 20%.

Though, the syllabus is quite similar for both the examinations (CEED And NIFT)


Hope this helps!
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