Hello aspirant,

See the marks u have score dis just a bit low for u to grab a seat in the good college under Mumbai University to pursue ur higher studies in the field of ur interest under btech courses. I m providing u a link for ur help.

https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/articles/mht-cet-cutoff/amp&ved=2ahUKEwjF4pKHraPiAhWQfisKHbUBDOcQFjAKegQIAhAB&usg=AOvVaw1o-AknZcI0tdutT8qeuHMQ&ampcf=1&cshid=1558123261167

Here the Total percentile is being calculated by using the formulae:

{(No.of students with marks less than 57 marks )/(Total number of students appeared  in the MHCET exam )}*100

So as you see that you have to know that No. of students that scores below 57 marks and the total

Hello aspirant,

According to MH - CET 2018 results, a score between 165 (Highest) - 149 is equivalent to 99.99 percentile , a score of 136 is equivalent to 99.88 percentile and a score of 113 is equivalent to 98.07 percentile .

Hope it helps!

Hello Aspirant,

With the mentioned marks your approximate rank would range between 1500-2000 which is based upon previous years data. It's important to note that the rank changes yearly based upon several factors like difficulty of exam, number of students appeared, etc.

To get a list of colleges in which

Hello Aspirant,

With 89 marks in MHT-CET your approximate percentile would range between 19,001 – 32,000 which is based upon previous years data.

Also to get a list of colleges you can get a seat into your desired branch you can use our MHTCET college predictor tool below

https://www.careers360.com/mht-cet-college-predictor?ici=cp-listing_root&icn=MHT-CET-College-Predictor

Hope

Hey aspirant,

Your chances seem very less for admission in PICT for IT branch.

According to previous year's data, the MHTCET cut off percentile for Open Category home University for Information Technology was 99.3789967( corresponding rank 1238) and that for other state university was 99.6407958 ( corresponding rank 662).

Although

Hello

101 is less score to get instrumentation engineering college in Mumbai. As this branch is not available in every college so cutoff goes high. You can wait till the last round so that there is chance to get a college.

Hope my answer will help you

Thank you

Hey friend!

Authorities will calculate percentile scores of the candidate’s upto five decimal places. The formula that will be used to calculate MHT CET 2020 score is:

MHT CET Percentile Score = 100 * (Number of candidates in exam with normalized marks ≤ the candidate) ÷ Total number of candidates

Hey,

Based on previous year trends, with 110 marks you can get a rank around 15000-16000 with a percentile between 99-90.

Based on previous year cut off, you can get the following colleges in Pune -

• Jayawantrao Sawant College of Engineering - BE Computer Engineering
• MIT Academy of Engineering -